How to differentiate Chrome and Safari - PHP

We would always like to provide our website visitors different services based their browser like Chrome Extension, Opera Add-on, Internet Explorer Tool-Bar etc.

For which we need to find what kind of browser our user is using to view our website.

So how do we find it?

Its simple : we use a preg_match() function for the purpose.

It takes basically two parameters :

  • The first is a search key enclosed in both "" as well as //. Example : "/chrome/"
  • The second is the string in which we need to search the Key.
Following is the codes for analyzing the famous browsers; Chrome, IE, FireFox, Opera and Safari.

   echo "This is Google Chrome code";

   echo "This is Internet Explorer code";

   echo "This is Opera code";

   echo "This is FireFox code";

   echo "This is Safari code"; ?>

Now why do we need this topic at all?

When I executed this code I got a similar result for both Chrome and Safari. They are as follows :

  • Chrome : Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/535.19 (KHTML, like Gecko) Chrome/18.0.1025.168 Safari/535.19
  • Safari : Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/534.57.2 (KHTML, like Gecko) Version/5.1.7 Safari/534.57.2
So you see there is really small difference in the output. A Chrome string is there in Chrome's output and not in Safari's.

But there is a Safari in both the outputs. Now, describe the topic we are on; Differentiate Safari from Chrome.

Use If-Else tree : Chrome's contains a "Chrome" word while Safari's not. So check if "Chrome" key is there in the $_SERVER["HTTP_USER_AGENT"], else check for the "Safari" key. While the reverse tree gives true for both the sentences and Chrome's output will not work.

Once again we solved an another problem.

Have a nice day in your website!


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